Parse an int from a string

[Mike Oxenfire]

I've been trying to get an integer from a scanned string and can't seem to get it to work. Here's my code:

 Scanner scan = new Scanner (System.in)
		input = scan.nextLine().toLowerCase();
		String[] qty1 = input.split("@");
		qty.add (Integer.parseInt (qty1[0]));

The idea is to enter an item @ quantity e.g "Shirt @ 2" and put shirt into one ArrayList and qty into another.
qty holds Integers.
Here's the exception I get, it's thrown at the last line of shown code:

Exception in thread "main" java.lang.NumberFormatException: For input string: "shirt "
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)

Thanks in advance.

[Christopher Nortje]

If the input is "Shirt @ 2" and you split using "@" you would have an array like this:
qty1[0] ="Shirt ";
qty1[1] =" 2";
You need to access the second value at the second index instead of the first:
Example
qty1[1]
Remember to trim() your String as your numeric value contains a space.

[Campbell Ritchie]

You can also use the next() and nextInt() methods of Scanner to read the "Shirt" "@" and 2 separately from the input.

[Campbell Ritchie]

You can also change the delimiter on your Scanner to include whitespace and the at sign @. Beware of the nextLine() method after a nextXXX() method; there is a risk of it returning an empty line.

[Campbell Ritchie]

. . . adn welcome to the Ranch

[Girish Amara]

Christopher Nortje is correct. That is the exact reason.