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Get the remaining part of a line of text in BASH Shell  RSS feed

 
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Consider the following text,

XML Message after final transformation

Please let me know in Unix, the Bash shell expression/script (without using sed/awk/etc...) that will return the following when the word after is passed as paramter.

final transformation

One restriction being, delimiter (space) should not be considered.
 
author and jackaroo
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We try not to answer homework questions on this site.

Perhaps you can demonstrate what you have already done, and we can provide help?
 
It is sorta covered in the JavaRanch Style Guide.
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