KB Practice Exams - Practice Test 4 Q5

[Fernando Martinez]

Hi to everyone,

I have two doubts with the following question,

1. Just to be sure, in line 6 "y" doesn't have a default value (so its null), the only member variables which get a default value are primitives right?
2. Test in line 14 should not print "1" in the first 3 iterations (i=0,1,2), so why the correct answer is C? Can you explain me please? I mean ^ is only true when only one of the tests is true, when i=0 then x=0, then x<2 true and x<10 true, so why does it gets printed?

Thanks in advance
Fernando

3. public class Honcho {
4. static boolean b1 = false;
5. static int z = 7;
6. static Long y;
7. public static void main(String[] args) {
8. for(int i = 0; i < 4; i++)
9. go(i);
10. }
11. static void go(int x) {
12. try {
13. if((x == 0) && (!b1 && z == 7)) System.out.print("0 ");
14. if(x < 2 ^ x < 10) System.out.print("1 ");
15. if((x == 2) &&
(y == null | (y.longValue() == 0))) System.out.print("2 ");
16. if(z <= (x + 4)) System.out.print("3 ");
17. }
18. catch(Exception e) { System.out.print("e "); }
19. } }

What is the result?
A. 0 1 2 3
B. 1 e 1 3
C. 0 1 e 1 3
D. 0 1 1 1 1 3
E. 1 1 1 2 1 3
F. 0 1 1 1 2 1 3
G. Compilation fails.

[gaurav gupta sitm]

see image

[Fernando Martinez]

Thanks, it was kind of obvious..... :-)

[Scotty Mitchell]

Fernando Martinez wrote:Thanks, it was kind of obvious..... :-)

Nothing is obvious in these type of questions! The fact that short circuiting doesn't occur at line 14 makes a difference watch out for the || or |!