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ArrayList.indexOf

 
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I am looking at the following code snippet in page 580



I am struggling to understand this line



The indexOf method is describe in the Javadocs as


Returns the index of the first occurrence of the specified element in this list, or -1 if this list does not contain the element. More formally, returns the lowest index i such that (o==null ? get(i)==null : o.equals(get(i))), or -1 if there is no such index.



But i still dont understand how it works in the above example because:

- Dog does not override the equals() method
- Dog does not implement Comparable or Comparator interfaces

Infact it would have been correct if == was used but i dont understand how equals works in this case. How exactly does indexOf find that dog is in index 0?




 
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If you don't override equals() than the equals() method inherited from Object is used. That method just uses ==

John
 
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John Stark wrote:If you don't override equals() than the equals() method inherited from Object is used. That method just uses ==

John



Oh ofcourse. i forgot about that.

Thanks
 
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