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Enthuware Simulator Question (SCWCD 5)

 
Mohit G Gupta
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Enthuware Test

Consider the following code snippets. What will be displayed on the browser when a GET request is sent to FirstServlet assuming that the buffer is large enough to hold all the data before sending the data to the client?


Select 1 correct option.
a.Only Page1 and Page3


b.Only Page2


c.Page1, Page2, and Page3


d.IllegalStateException at Runtime.
See general comments.

e.Compilation Error.


General Comments
The servlet specification mandates that when a request is "forwarded" to another resource, the buffer should be cleared of the contents generated by the forwarding resource. Therefore, only Page2 will be sent to the client. However, calling forward() means that the request processing is delegated to the callee resource permanently. So, although the control does return to the caller resource [because rd.forward() is just a regular method call], the caller resource cannot generate any output after the call to forward().
In this case, FirstServlet is trying to send output to the client after calling forward() and so an IllegalStateException will be thrown.



In the doGet() of FirstServlet:

In the doGet() of SecondServlet:


--------------------------------------------------------------------------------------------
I tired the same example:

doGet() of Source servlet


doGet() of Destination Servlet



As per the general comments ,I should get an Exception .
But,I am able to see
Destination in the Browser output when i ran Source Servlet and request is forwarded successfully.

Why such different behavior ?
 
Ankur Gargg
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Hi Mohit

1)You only get IllegalStateexception when the caller of forward() method has committed response which in case it has not.

2)Also after the forward() method returns any attempt to write to output will not be entertained and just ignored.

 
Mohit G Gupta
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so Ankur ,Only Page2 is the correct answer
 
Ankur Gargg
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yes mohit.Whatever is written by forwarded resource will result in ultimate response.
 
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