# Why does (0 % n) not generate an arithmetic exceptoin

posted 4 years ago

The % operator (remainder/mod operator) return the remainder of the expression by dividing the first number with the second number.

If the first number is 0 (e.g. 0 % 5) the result is always 0. Why does this not return an ArithmeticException?

The % operator (remainder/mod operator) return the remainder of the expression by dividing the first number with the second number.

If the first number is 0 (e.g. 0 % 5) the result is always 0. Why does this not return an ArithmeticException?

posted 4 years ago

Does 0 / 5 give you any exception?

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