EJB 3.0 Remote interface invocation issue!!

[Mohammed Shafique]

Hi i am trying to develope simple EJB Application after a long time & facing a strange problem,
i have developed a simple Enterprise Application , having a Web module & an EJB module,
and using JSP page as a client, in jsp page i have written code like this given below

public HelloBeanRemote hel = null;
  public void jspInit()
  {
	  try{
		  InitialContext ctx = new InitialContext();
		  HelloBeanRemote hel = (HelloBeanRemote)ctx.lookup("Hello/HelloBean/remote");
		  [b]System.out.println(hel.hello("hi")+ " Returned this");[/b]		 
                    System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++");
		  System.out.println(hel);
		  
	  }catch(Exception e)
	  {
		  e.printStackTrace();
	  }
  }

when i am running application i can see this System.out.println(hel.hello("hi")+ " Returned this") line output on console , but when
i am trying to show this output on my web page using this code

String name ="";
  try{
	 String result ="";  
	 System.out.println(name + " before getting request parameter");
	 name = request.getParameter("name");
	 System.out.println(name + " After getting request parameter");
	 if(name != null){
		 System.out.println("in if before invokation");
		 result = result + hel.hello(name);
		 if(null == hel.hello(name)){
		 out.println("in if after invokation " + result + " its returned" );
		 out.println(result);
		 }else{
			 out.println("xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx");
		 }
	 }
 }catch(Exception e)
 {
	 System.out.println("-------------------------------------");
 }

in the same JSP page i am getting null, in fact i tried to debug it, & found that control is not reaching to this
result = result + hel.hello(name); in the above mentioned, later fragment of code.
why it is happening, i have checked all dependencies of EAR file, & WER file, even i m facing this problem, what is my mistake,

Can any one please help me out,

[Jeanne Boyarsky]

What exception is happening here:

}catch(Exception e)
{
System.out.println("-------------------------------------");
} 

You'll need to add code to find out. Right now, the code hides the exception so you can't know what is wrong.

Also, note it is bad practice to put Java code in new JSPs.

[massimiliano cattaneo]

Hello,
Who sets the parameter named "name" ?
if this "name = request.getParameter("name");" return null, all the code is skipped so the behaviour is right.

What is printed by the two lines of code ?

System.out.println(name + " before getting request parameter");
name = request.getParameter("name");
System.out.println(name + " After getting request parameter"); 

Please use the "code" to post the code in the forum