• Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other Pie Elite all forums
this forum made possible by our volunteer staff, including ...
Marshals:
  • Campbell Ritchie
  • Tim Cooke
  • paul wheaton
  • Paul Clapham
  • Ron McLeod
Sheriffs:
  • Jeanne Boyarsky
  • Liutauras Vilda
Saloon Keepers:
  • Tim Holloway
  • Carey Brown
  • Roland Mueller
  • Piet Souris
Bartenders:

Noob error :org.hibernate.exception.SQLGrammarException: could not insert [com.sample.Person]

 
Ranch Hand
Posts: 477
Eclipse IDE Tomcat Server Java
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
I'm trying to set up a small working sample of Hibernate that I found here.
However when I run the code I get the follwing error
.

But I already have a table by the name person in the database and here's my hibernate.cfg.xml



Content of the postgresql log file


It would be great if anyone could point out what Im doing wrong, as this is my first attempt at Hibernate.
Thanks!
 
Vic Hood
Ranch Hand
Posts: 477
Eclipse IDE Tomcat Server Java
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
UPDATE: Was able to fix that error. However I get the following error now



What I dont understand is why is hibernate looking at person0_ instead of person, any input on this could be helpful. Thanks!
 
Greenhorn
Posts: 1
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
It is because hibernate queries are later converted to sql queries and table aliases are created in the queries. In this case, person0_ is an alias for the table person.
 
reply
    Bookmark Topic Watch Topic
  • New Topic