Throws Exception on the main method

[Gil Shoam]

public class Value{
      private int num=0;
         public Value() throws Exception{
             if(something)
                 throw new Exception();
         }
     }

    public static void main(String[] args) throws Exception{
        Value val= new Value();
        
    }
       

in the above code, where is the Exception actually handled? It just keeps getting thrown...
isn't there supposed to be a try/catch somewhere to define what happens if the Exception is thrown?
I know that if I would delete the "throws" from the main, I would be forced to try/catch, but if main throws where is it caught?
Thanks for your time

[Jeff Verdegan]

Gil Shoam wrote:
in the above code, where is the Exception actually handled?

By the JVM

isn't there supposed to be a try/catch somewhere to define what happens if the Exception is thrown?

It's in the JVM, where it calls main().

[Gil Shoam]

Thanks for your answer but it didn't really answer my question.
With try/catch I define what happens in case of an exception. (for example i can print "an exception occured"). In this case (main throws) what actually happens? what does the program do?

[Chetan Sarnad]

Gil Shoam wrote:Thanks for your answer but it didn't really answer my question.
With try/catch I define what happens in case of an exception. (for example i can print "an exception occured"). In this case (main throws) what actually happens? what does the program do?

Well, I do not see any try/catch block in your code. Place your try/catch block in the code, try executing the code and repost for further queries.
As answered by Jeff, the jvm is currently doing the exception handling. You can speicfy the behaviour of the application/code in case of exception by using the catch block.

[Darryl Burke]

The JavaTM Virtual Machine Specification -- 2.16 Exceptions

[Campbell Ritchie]

Gil Shoam wrote:. . . In this case (main throws) what actually happens? what does the program do?

Bruce Eckel explains it for unchecked Exceptions. If you write

public static void main(String[] args) throws Exception
{
   ...
}

... exactly the same happens if that Exception is thrown from the main method.

[Jeff Verdegan]

Gil Shoam wrote:Thanks for your answer but it didn't really answer my question.
With try/catch I define what happens in case of an exception. (for example i can print "an exception occured"). In this case (main throws) what actually happens? what does the program do?

public class E {
  public static void main(String[] args) throws Exception {
    throw new Exception("Boo!");
  }
}

Run that and see what happens.

If your next question--or what you really meant to ask--is "How/why does that happen?" then the answer is, as I said, because the JVM's code that calls main is catching the exception and call e.printStackTrace().