enhanced for loop problem -- from a mock

[Js Kaur]

I got this code from a mock .....

        int[] arr = {1, 2, 3, 4};
        for (int ii : arr) {
            System.out.println(ii);
        }
        for (int ii : arr) {
            System.out.println("arr["+ii+"] = 0");
            arr[ii] = 0;
        }
        for (int ii : arr) {
            System.out.println(ii);
        }

output is ::

1
2
3
4
arr[1] = 0
arr[0] = 0
arr[3] = 0
arr[0] = 0
After ....
0
0
3
0


Why in the second loop array index's are like 1,0,3, 0 shouldn't it be arr[0], arr[1], arr[2], arr[3]

[Ankit Garg]

When the loop runs the first time, ii contains 1 as arr[0] contains the value 1. The loop prints arr[1]=0 (as ii contains the value 1). Then you set arr[ii] to 0 i.e. arr[1] is set to 0.
Then when the loop run's 2nd time, ii contains the value of arr[1] which is 0. The loop prints arr[0]=0 (as ii contains the value 0). Then you set arr[ii] to 0 at this point ii is 0 so you set arr[0] to 0.
Then when the loop run's 3rd time, ii contains the value of arr[2] which is 3. The loop prints arr[3]=0 (as ii contains the value 3). Then you set arr[ii] to 0 at this point ii is 3 so you set arr[3] to 0.
Then when the loop run's 4th time, ii contains the value of arr[3] which is 0. The loop prints arr[0]=0 (as ii contains the value 0). Then you set arr[ii] to 0 at this point ii is 0 so you set arr[0] to 0...

[ayush raj]

Good example for the fundamentals . Each time the for loop modifies the contents of the array and the iterator works accordingly !!

[Henry Wong]

Js Kaur wrote:I got this code from a mock .....

Please QuoteYourSources -- meaning which mock?

Henry