How to Pass Cursor Row as a parameter to another Function?

[Sandeep John]

Hi All,

I Have Cursor

CURSOR ABC IS
Select * from XYZ;

BEGIN

FOR REC IN ABC LOOP
FUNCTION();
END LOOP;

Now I need to pass each row from cursor ABC as a parameter to FUNCTION().

Can some one tell me how to do that?

[Gene Hilpert]

I'm not sure if you want to call the function for each row in the select or if you want pass the cursor to the function.
For the first case include the function in the select
I.E.

select col1,col2,functioncall(col1) 
from table;

For the second

CREATE OR REPLACE FUNCTION schemaname.con_list (p_cursor IN SYS_REFCURSOR)
  RETURN  VARCHAR2
IS
  l_return  VARCHAR2(32767);
  l_temp    VARCHAR2(32767);
BEGIN
  LOOP
    FETCH p_cursor
    INTO  l_temp;
    EXIT WHEN p_cursor%NOTFOUND;
    l_return := l_return || ',' || l_temp;
  END LOOP;
close p_cursor;
  RETURN LTRIM(l_return, ',');
END;

Then call it like:

SELECT ICEO.concatenate_list (
          CURSOR (SELECT col10
                   FROM schemaname.tablename))
          AS newlist
  FROM DUAL;

Hope this helps.

[Sandeep John]

I guess you dint get my question correctly, Let me explain more detail..

From above example I have Cursor ABC.

Instead of doing
FUNCTION(REC.Col1, REC.Col2, REC.Col3)


I wanna send each record completely, what is the correct procedure of doing below

FUNCTION(REC);

[Martin Vashko]

Welcome to the Ranch, Sandeep!

Please re-read Gene's answer. Does it pass individual columns from the cursor to the function or not?

Alternatively, you might perhaps use the %ROWTYPE attribute.