Exception code.

[Ritesh raushan]

what is the output of this program and how please explain .

class Exc0 extends Exception { } 
class Exc1 extends Exc0 { } /* Line 2 */
public class Test 
{  
    public static void main(String args[]) 
    { 
        try 
        {  
            throw new Exc1(); /* Line 9 */
        } 
        catch (Exc0 e0) /* Line 11 */
        {
            System.out.println("Ex0 caught"); 
        } 
        catch (Exception e) 
        {
            System.out.println("exception caught");  
        } 
    } 
}

[Campbell Ritchie]

We don’t simply answer such questions. Please explain what you think the output is, and we shall say whether we agree.
You must also tell us where the question comes from.

[Buddhika Mawella]

Hint : first think about java exception catching order.

[Matthew Brown]

Of course, the best way to find out for certain what the output is (once you've thought about what you think it should be) is to actually compile and run the code.

[Ritesh raushan]

ouput is (Ex0 caught) but i didn't understand how did.

[Tony Docherty]

What did you expect it to be and why?

[Gaurangkumar Khalasi]

Because of inheritance...

Exc0 e0 = new Exc1();

[Campbell Ritchie]

Gaurangkumar Khalasi wrote:Because of inheritance...

Exc0 e0 = new Exc1();

Correct. What you need to do is follow the path of execution, with a pencil on the code. You should be able to confirm that easily.