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logic operation

 
Greenhorn
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how to make if not method (OR) not method in java ???
cz the way i do it doesnt return the response i want to see


and here how i do it


if(!method1()||!method2()) // doesnt do the excepected result


if(!(method1())||!(method2())) //neither this do the excepected result

it doesnt show bugs

but the excution logic isnt what i want


what i want is if anyone of this methods return (not true) excute the next code


 
Bartender
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Hello there

It really depends on what your method1 and method2 does. If you return true say in method1, and check for !method1(), then this evaluates to false. Same goes for method2().
 
amr talaat
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K. Tsang wrote:Hello there

It really depends on what your method1 and method2 does. If you return true say in method1, and check for !method1(), then this evaluates to false. Same goes for method2().




METHOD1 RETURN TRUE
METHOD2 RETURN TRUE


I WANT TO DO THIS


WHILE (!method1(N1,N2)||!method2(N1,N2))
{

//EXCUTE THIS UNTIL ONE OF THE METHODS RETURN FALSE


}
 
amr talaat
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amr talaat wrote:

K. Tsang wrote:Hello there

It really depends on what your method1 and method2 does. If you return true say in method1, and check for !method1(), then this evaluates to false. Same goes for method2().




METHOD1 RETURN TRUE
METHOD2 RETURN TRUE


I WANT TO DO THIS


WHILE (!method1(N1,N2)||!method2(N1,N2))
{

//EXCUTE THIS UNTIL ONE OF THE METHODS RETURN FALSE


}



TO put you in the picture excuting the code in the body affects the parameters of method1 and method 2 which affect its return value

 
Bartender
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amr talaat wrote:
I WANT TO DO THIS


WHILE (!method1(N1,N2)||!method2(N1,N2))
{
//EXCUTE THIS UNTIL ONE OF THE METHODS RETURN FALSE
}





The above says, "keep looping as long as m1() and m2() both return true." That's what "while" means in English and in Java. You seem to have been treating "while" as if it meant "until."

Note that when using &&, if m1() returns false, it won't bother evaluating m2(), wince it can't affect the outcome of the if condition. If you want m2() to execute even if m1() returns false, use & instead of &&.
 
Bartender
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amr talaat wrote:I WANT TO DO THIS
WHILE (!method1(N1,N2)||!method2(N1,N2))...


Amr, please KeepItDown (←click). Posting in all caps is akin to shouting, and it doesn't make pleasant reading.

I think Jeff has basically answered your question, but I'd also suggest that you try to avoid "negative" (!) logic if you can.
if (true)
is generally a lot easier to follow than
if (!false)
especially if the expression is a compound one.

Winston
 
lowercase baba
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Do you want your body to execute when AT LEAST one method returns false, or when EXACTLY one method returns false?
 
Marshal
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It is worth remembering de Morgan’s law for this sort of problem. If p and q are any boolean values:-
!p && !q ≡ !(p || q)
!p || !q ≡ !(p && q)
Remember ! has a higher precedence than && or ||.
 
amr talaat
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thanks guys morgan law and (&) did the trick
 
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