Srinivas Palam wrote:Thanks for your Reply. I am assuming the same when Init(7) is involved. It will invoke its implicit super(with one argument).
No, the implicit call from a subclass constructor is to the super() no-args constructor.
If there is no no-args constructor in the superclass then compilation will fail.
You can explicitly call a specific superclass constructor from the subclass constructor, and that call must be the first statement in your subclass constructor.
Regards,
Al