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global and local variable concept  RSS feed

 
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//its output is :
1
2
why the value of x doesnt changed??
 
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bhavneet kaur wrote:
class C1
{

static int s;

public static void main(String a[])
{

C1 obj=new C1();
obj.m1();
System.out.println(s);
}

void m1()
{
int x=1;
m2(x);
System.out.println(x+"");
}

void m2(int x)
{
x=x*2;
s=x;

}
}

//its output is :
1
2
why the value of x doesnt changed??

Enkita mody
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Joined: Aug 06, 2012
Posts: 294

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x is a method local variable of m1.it doesn't belongs to m2 method.m2 has its own another x.
 
bhavneet kaur
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it means if "s" would also be inside main function then it would also not changed
 
Enkita mody
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bhavneet kaur wrote:
it means if "s" would also be inside main function then it would also not changed



s is a static variable, you can't declare it in static method main.
 
bhavneet kaur
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but i have executed it again with s inside main still its giving same output
 
bhavneet kaur
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why so i have declared it inside main as int s; so it becomes static because it is now declared inside static main method
 
Enkita mody
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bhavneet kaur wrote:
why so i have declared it inside main as int s; so it becomes static because it is now declared inside static main method



No,int s is not a static variable until you write static int s.
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