I have downloaded and installed jdk-7u10-windows-i586 in C:\Java\jdk1.7.0_10 directory and then under windows XP at system property>advanced>environmental variables>system variables I added a new variable JAVA_HOME with value C:\Java\jdk1.7.0_10 and also added %JAVA_HOME%\bin; to the beginning of path.
Now at command prompt when I type javac -version it says "javac is not recognized as internal or external command " but when I type java -version it comes back wit "1.7.0_10'
Checking that your JDK is configured properly at "://www.coderanch.com/how-to/java/how-to-create-java-program " is telling me javac -version should return the version, why when I type javac it's not recognized???, it does not compile either.
trying to compile with java at C:\java\src>java MooseGreetings.java gives error "could not find or load class MooseGreetings.java" , I have made sure the file " MooseGreetings.java" exists under java/src , I created this sample program with a text editor that does not append extra extensions to file name. So I have 2 problems to start:
1. Javac is not recognized
2. sample program can not be found
Could anyone help me to start???
Marjorie Gyles wrote:All I did was add "C:\Java\jdk1.7.0_10\bin" to my path.
I do not fiddle around with PATH but put wrapping starting scripts (javac15, java15, javac16, java16, javac17, java17 etc.) which set the PATH locally and temporarily. So several versions of Java can coexist on the same box.
You can write things like export PATH=~/java/jdk1.2.2_03/bin:$PATH (*nix) or set PATH="c:\Program Files\java\jdk1.2.2_03\bin;%PATH% (Windows®).
You ought to check the syntax because I am unsure about both instructions. Those will alter the path temporarily
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