getting random numbers

[sudde gameeef]

i am making a game where i need to create object only onces randomly. <br/>
i can get random number by random object. but not sure how to put in if statment. <br/>





if()
System.out.println("random 1");
else if()
System.out.println("random 2");
else if()
System.out.println("random 3");

[Ramesh Pramuditha Rathnayake]

After you have got the random numbers, I think you could use a switch rather than an if statement..

[Ramesh Pramuditha Rathnayake]

And it's better if you explain your question further more...

[Winston Gutkowski]

sudde gameeef wrote:i am making a game where i need to create object only onces randomly. <br/>
i can get random number by random object. but not sure how to put in if statment. <br/>

I'm not sure I understand the question. Are you sure you've read and understood the java.util.Random API? (and BTW, it's 'Random', not 'random' - that sort of stuff is very important in Java).

The reason I ask is that I don't see any attempt to call one of its methods in your code.

Normally, I'd suggest using the online tutorials; but unfortunately they still seem to be stuck on using Math.random(), which is vastly inferior to the Random class. This page seems to provide a quick intro with a few examples though.

Winston

[sudde gameeef]

int x = r.nextInt(300);
     if(x > 0 && x < 100)
          System.out.println("random 1");
        else if(x > 100 && x < 200)
          System.out.println("random 2");
        else if(x > 200 && x < 300) 
               System.out.println("random 3");

i am not sure if this is the right way.

int x = r.nextInt(2);
     if(x == 0)
          System.out.println("random 1");
        else if(x == 1)
          System.out.println("random 2");
        else if(x == 2) 
               System.out.println("random 3");

[Ramesh Pramuditha Rathnayake]

Your second code is fine. But you have written lots of unnecessary codes in you first code.

int x = r.nextInt(300);
if(x < 100)
      System.out.println("random 1");
else if(x < 200)
      System.out.println("random 2");
else if(x < 300) 
      System.out.println("random 3");

This will give the same result as in yours. But this contains no unnecessary codes...


If you use code as in your 2nd example, it better to use switch..case statement!!

[Maneesh Godbole]

sudde gameeef wrote:

Like you were requested before, please check your private messages for an important administrative matter. Please note, this is not optional.

[Anayonkar Shivalkar]

If you need to create random number only once (and especially if you are not dealing with a series of random numbers), I would suggest to use 'random' method of 'Math' class.

It's quite easier than 'Random' class itself.

I hope this helps.

[Jesper de Jong]

Ramesh Pramuditha Rathnayake wrote:This will give the same result as in yours. But this contains no unnecessary codes...

Almost the same. The original code didn't print anything if x was exactly equal to 0, 100 or 200. Also, the condition (x < 300) is unnecessary, because r.nextInt(300) will always produce a number less than 300.

[Ramesh Pramuditha Rathnayake]

Jesper de Jong wrote:Almost the same. The original code didn't print anything if x was exactly equal to 0, 100 or 200. Also, the condition (x < 300) is unnecessary, because r.nextInt(300) will always produce a number less than 300.

You are right..!
I have done a greate mistake..!!!

Thank you..!

[Jesper de Jong]

I wouldn't call it a great mistake. But with computers and programs you always have to be really careful, especially with corner cases.

[Jeff Verdegan]

Anayonkar Shivalkar wrote:If you need to create random number only once (and especially if you are not dealing with a series of random numbers), I would suggest to use 'random' method of 'Math' class.

It's quite easier than 'Random' class itself.

I disagree with that. I don't think Math.random() is any easier to use. And particularly if you need an int, as the OP does here, Random is somewhat easier. And

[Anayonkar Shivalkar]

Yes. Maybe I'm more habitual with Math.random()

Generally, if I need random number ranging from 0 to n, I would go for

(int) (Math.random() * n)

[Campbell Ritchie]

But myRandom.nextInt(i) will do it more elegantly. I agree with Jeff.

[Anayonkar Shivalkar]

Yes. Just checked the API docs.

Looks like I gotta break my habits