This week's book giveaway is in the Cloud forum.
We're giving away four copies of Terraform in Action and have Scott Winkler on-line!
See this thread for details.
Win a copy of Terraform in Action this week in the Cloud forum!
  • Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other Pie Elite all forums
this forum made possible by our volunteer staff, including ...
  • Tim Cooke
  • Campbell Ritchie
  • Paul Clapham
  • Ron McLeod
  • Liutauras Vilda
  • Jeanne Boyarsky
  • Rob Spoor
  • Bear Bibeault
Saloon Keepers:
  • Jesse Silverman
  • Tim Moores
  • Stephan van Hulst
  • Tim Holloway
  • Carey Brown
  • Piet Souris
  • Al Hobbs
  • salvin francis

File Upload using SPRING REST API

Posts: 17
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator

I am trying to upload file using POSTMAN REST client. i have configured Content-Type=multipart/form-data;boundary=---------------------------sdjkahdj294919323195 and file=<file.txt>

This is my controller.

Added this in spring.xml

But when i send url http://localhost:8080/myapp/rest/uploadfile.json , i am getting HTTP Status 400 - The request sent by the client was syntactically incorrect ().

Can anyone help in finding the mistake.

Thanks in advance
Ranch Hand
Posts: 49
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
I think the issue is with the URL. Please check once as this bean cannot be identied with the given URL.

And one more thing the way you are handling the file stream would be problem for huge files.we need to take help of disk file to store it temporarly
please see below code if it is useful for you or not
boolean isMultipart = ServletFileUpload.isMultipartContent(request);

if (isMultipart) {

FileItemFactory factory = new DiskFileItemFactory();
ServletFileUpload servletFileUpload = new ServletFileUpload(factory);

try {

List items = servletFileUpload.parseRequest(request);
Iterator iter = items.iterator();
while (iter.hasNext()) {
FileItem item = (FileItem);
if (!item.isFormField()) {
String fileName = item.getName();
long fileSize = item.getSize();
String contentType = item.getContentType();
InputStream is = item.getInputStream();
    Bookmark Topic Watch Topic
  • New Topic