String constant pool

[Ritesh raushan]

why output is unequal.
class Pool
{
public static void main(String[] ar)
{
String s="abc";
String s1="ab";
s1=s1+"c";//why s1 is not created in pool this is also literal
if(s==s1)
System.out.println("equal");
else
System.out.println("unequal");
}
}

[Mansukhdeep Thind]

Always use code tags:

public class PoolTest
{
public static void main(String[] ar)
{
String s="abc";
String s1="ab";
s1=s1+"c";//why s1 is not created in pool this is also literal
if(s==s1)
System.out.println("equal");
else
System.out.println("unequal");
}
}

Better now. Isn't it? When you say

s1 = s1 + "c";

, do you know what happens? Or let me put it this way, how many String objects are out there?

[Winston Gutkowski]

 

Ritesh raushan wrote:s1=s1+"c";//why s1 is not created in pool this is also literal...

"c" might be a literal, but 's1 + "c"' is not; that's why.

And in fact "c" WILL be put into the pool as a result of that statement (at least, I'm pretty sure it will; you can test it).

Winston

[Mansukhdeep Thind]

 

Winston Gutkowski wrote:

Ritesh raushan wrote:s1=s1+"c";//why s1 is not created in pool this is also literal...

"c" might be a literal, but 's1 + "c"' is not; that's why.

And in fact "c" WILL be put into the pool as a result of that statement (at least, I'm pretty sure it will; you can test it).

Winston

You gave it away Winston. I wanted to get it out of him. Anyways, its done now.