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jstl problem in Spring MVC

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posted 16 years ago

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I am working on examples from "Developing a Spring Framework MVC application", it is the pdf which is bundled along with the Spring framework download.
I am using Tomcat5.5 and Spring 2.5 and IE6.0
The application which I have created doesn't display c

ut value, my jsp displays ${now} instead of now's value, neither my jsps understand the following tag

I have included jstl.jar and standard.jar which came along with the spring distribution.
Also the .java of my jsp which doesnt display the tags is:
package org.apache.jsp.WEB_002dINF.jsp;

import javax.servlet.*;
import javax.servlet.http.*;
import javax.servlet.jsp.*;

public final class hello_jsp extends org.apache.jasper.runtime.HttpJspBase
    implements org.apache.jasper.runtime.JspSourceDependent {
 
  private static java.util.Vector _jspx_dependants;
 
  private org.apache.jasper.runtime.TagHandlerPool _jspx_tagPool_c_out_value;
 
  public java.util.List getDependants() {
    return _jspx_dependants;
  }
 
  public void _jspInit() {
    _jspx_tagPool_c_out_value = org.apache.jasper.runtime.TagHandlerPool.getTagHandlerPool(getServletConfig());
  }
 
  public void _jspDestroy() {
    _jspx_tagPool_c_out_value.release();
  }
 
  public void _jspService(HttpServletRequest request, HttpServletResponse response)
        throws java.io.IOException, ServletException {
 
    JspFactory _jspxFactory = null;
    PageContext pageContext = null;
    ServletContext application = null;
    ServletConfig config = null;
    JspWriter out = null;
    Object page = this;
    JspWriter _jspx_out = null;
    PageContext _jspx_page_context = null;

try {
      _jspxFactory = JspFactory.getDefaultFactory();
      response.setContentType("text/html");
      pageContext = _jspxFactory.getPageContext(this, request, response,
      null, false, 8192, true);
      _jspx_page_context = pageContext;
      application = pageContext.getServletContext();
      config = pageContext.getServletConfig();
      out = pageContext.getOut();
      _jspx_out = out;
 
      out.write("\r\n");
      out.write("\r\n");
      out.write("\r\n");
      out.write("<html>\r\n");
      out.write("<head>\r\n");
      out.write("<title>Hello :: Spring Application</title>\r\n");
      out.write("</head>\r\n");
      out.write("<body>\r\n");
      out.write("<h1>Hello - Spring Application</h1>\r\n");
      out.write("<p>Greetings, it is now ");
      if (_jspx_meth_c_out_0(_jspx_page_context))
        return;
      out.write("</p>\r\n");
      out.write("</body>\r\n");
      out.write("</html>");
    } catch (Throwable t) {
      if (!(t instanceof SkipPageException)){
        out = _jspx_out;
        if (out != null && out.getBufferSize() != 0)
          out.clearBuffer();
        if (_jspx_page_context != null) _jspx_page_context.handlePageException(t);
      }
    } finally {
      if (_jspxFactory != null) _jspxFactory.releasePageContext(_jspx_page_context);
    }
  }
 
  private boolean _jspx_meth_c_out_0(PageContext _jspx_page_context)
          throws Throwable {
    JspWriter out = _jspx_page_context.getOut();
    //  c :-o	 ut
    org.apache.taglibs.standard.tag.rt.core.OutTag _jspx_th_c_out_0 = (org.apache.taglibs.standard.tag.rt.core.OutTag) _jspx_tagPool_c_out_value.get(org.apache.taglibs.standard.tag.rt.core.OutTag.class);
    _jspx_th_c_out_0.setPageContext(_jspx_page_context);
    _jspx_th_c_out_0.setParent(null);
    _jspx_th_c_out_0.setValue(new String("${now}"));
    int _jspx_eval_c_out_0 = _jspx_th_c_out_0.doStartTag();
    if (_jspx_th_c_out_0.doEndTag() == javax.servlet.jsp.tagext.Tag.SKIP_PAGE)
      return true;
    _jspx_tagPool_c_out_value.reuse(_jspx_th_c_out_0);
    return false;
  }
}

Eclipse says that org.apache.jasper could not be resolved and lot more similar errors.I believe that it is jstl problem. Could anybody shed some light on it?
Thanks,

Aditi

Christophe Verré

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posted 16 years ago

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my jsp displays ${now} instead of now's value

I think that you need to configure your web.xml properly. Check this FAQ.

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K Aditi

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posted 16 years ago

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I checked my web.xml and modified it according to FAQ entry.But that did not do the trick.My web.xml is as following:

<?xml version="1.0" encoding="ISO-8859-1"?>
 
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
    "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
<a href="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"" target="_blank" rel="nofollow">http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"</a> id="WebApp_ID" version="2.5">
    <display-name>web app name here</display-name>
 
<display-name>Welcome to Tomcat</display-name>
<description> Welcome to Tomcat </description>

<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>springapp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springapp</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
</web-app>

Aditi

Christophe Verré

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posted 16 years ago

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It doesn't look like the FAQ

Remove the following :

And I think that in Tomcat 5.5 you should be using the Servlets 2.4 and JSP 2.0 web.xml. The one at the bottom of the FAQ.
[ September 29, 2008: Message edited by: Christophe Verre ]

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K Aditi

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posted 16 years ago

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Hey Thanks a lot!

That was indeed the problem!

Aditi

K Aditi

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posted 16 years ago

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Just an after-thought,
Now my web.xml looks like

<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee <a href="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"" target="_blank" rel="nofollow">http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"</a>
     version="2.4">
 
<display-name>Welcome to Tomcat</display-name>
<description> Welcome to Tomcat </description>

It does not have a DOCTYPE tag...for now it works just fine.But in which situations DOCTYPE tag is unavoidable? I googled for DOCTYPE tag and the gist of what I read is web.xml should have DOCTYPE tag.Obviously, I don't agree.Am I correct?

Aditi

Christophe Verré

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posted 16 years ago

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You usually use DOCTYPE to declare a DTD. Servlets 2.4 use an Xml Schema instead of a DTD, therefore the DOCTYPE is not used.

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K Aditi

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posted 16 years ago

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Thanks for the reply!

Aditi