# help in tic tac toe program

ten doeschate

Greenhorn

Posts: 16

posted 3 years ago

in the attached file

i have problem with the percentage_games and percentage_games1 variable

it is not updating correctly as when both X and O have 1won 1 game each it should show percentage as 50 but it is showing 100 and 0

please help!!

my program is as follows:

i have problem with the percentage_games and percentage_games1 variable

it is not updating correctly as when both X and O have 1won 1 game each it should show percentage as 50 but it is showing 100 and 0

please help!!

my program is as follows:

posted 3 years ago

- 1

Welcome to the Ranch!

Keep in mind that the division operator denotes integer division if both operands are integers, and floating-point division otherwise. Yours is the first case - both of your operands are integers (e.g. 1/2 = 0 by integer division), hence the results you get.

Keep in mind that the division operator denotes integer division if both operands are integers, and floating-point division otherwise. Yours is the first case - both of your operands are integers (e.g. 1/2 = 0 by integer division), hence the results you get.

The quieter you are, the more you are able to hear.

Piet Souris

Rancher

Posts: 1400

29

ten doeschate

Greenhorn

Posts: 16

posted 3 years ago

can yu help me how to use showStatus() in above program by extending JApplet

it is showing error as NullPointer Exception

please help

it is showing error as NullPointer Exception

please help

Piet Souris

Rancher

Posts: 1400

29

posted 3 years ago

I can't find a "showStatus()" method in your code.

And, is it your intention to run "TicTacToe" as an applet?

A remark: you are using expressions like "if (letter == "X") {...}".

Since you are using string literals here, you might get away with this. But you should always use "if (letter.equals(someOtherString)) {...}".

And, is it your intention to run "TicTacToe" as an applet?

A remark: you are using expressions like "if (letter == "X") {...}".

Since you are using string literals here, you might get away with this. But you should always use "if (letter.equals(someOtherString)) {...}".