Converting String to char

[Dan Grindstaff]

Hello, I am trying to grab a letter from an array of numbers (char) and printout the remaining characters. So user is prompted to type in a character and the program prints out the remaining numbers left in the alphabet array. The problem is, when the scanner reads 'next' it seems to make the char a String. Any ideas to prevent or get around this is greatly appreciated.

import java.util.*;

public class Alphabet {

    public static void main(String args[])
    {
        char L;

        char[] characters = new char[]{'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'};
        Scanner in = new Scanner(System.in);
        System.out.println("Enter a letter");
        L = (char)in.next();

        assert characters != null;
        System.out.println("L is: " + L);

        for (int i = 0; i<characters.length; i++) {
            if (L.equals(characters[i])) {
                System.out.println("Letters match");
            }else{
                System.out.println("Letters do not match");



            }
        }
    }

}

>

[Ron McLeod]

Scanner's next() method returns a String. If you want to retrieve a character at a particular position, then you could use String's charAt() method.

Also, L is a char, which is a primitive, and does not have a equals() or any other method.

[Dan Grindstaff]

Thanks. Here is my code now:

import java.util.*;

public class Alphabet {

    public static void main(String args[])
    {
        char character;
        int i;
        char[] charArray = new char[]{'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'};
        Scanner in = new Scanner(System.in);
        System.out.println("Enter a letter");

        System.out.println(character=(in.next().charAt(0)));
        assert charArray != null;


        for ( i = 0; i<charArray.length; i++) {
            if (charArray[i]==character) {
                System.out.println("Letters match");
                System.out.println("Character is: " + character );
                System.out.println(Arrays.toString(charArray));
            }else{
                //System.out.println("Letters do not match");




            }
        }
    }

}

I need a way to print the remaining alphabet after the letter chosen. Not sure how to do that.>

[Ron McLeod]

One idea would be to save the position of the letter in the array found during search that you are already doing, then loop-through the array a second time, but this time starting after the position where the letter was found.