constructor with parameters

[bairava surya]

public class TestClass
{
    
    public TestClass(String k){System.out.println(k);}

   
    public static void main(String[] args) 
    {
           try   
            {
            hello();
            }
          catch(Exception e){System.out.println(e);}
    }
    
    static void hello() throws MyException
      {
        int[] dear = new int[7];
        dear[0] = 747;
        foo();
    }
    
    static void foo() throws MyException
      {
        throw new MyException("Exception from foo");
      }
}

class MyException extends Exception 
     {
   public MyException(String msg)
         {
        super(msg);
          }
     }

explain how catch block act as constructor with parameter?

[Campbell Ritchie]

bairava surya wrote: . . .
explain how catch block act as constructor with parameter?

What does that question mean?

You have a constructor which does not act as a constructor, because it does not initialise any fields. You have a method which throws an Exception and that Exception is caught. But there is no relationship between the Exception and the constructor.

[bairava surya]

explain me how super keyword works in this program?

[Henry Wong]

bairava surya wrote:explain me how super keyword works in this program?

The super keyword, as used in your example, in the constructor of the subclass, is choosing which constructor of the superclass to use to initialize the superclass components of the subclass. By default, if you don't have that call, it will use the no-arg (default) constructor of the superclass.

Henry

[bairava surya]

explain me how the content in the msg(super(msg)) is passed to catch block how it works?

[Campbell Ritchie]

Do you mean, “what does super(...); in a constructor mean?“

Start with this part of the Java® Tutorials and this section.