Reversing an integer

[Ahsan Bagwan]

I'm solving this problem from leetcode. I am handling the sign by adding string to the start of the string. But after running this problem online the test case failed. Could someone point out what corner case I am not handling here?

public class Solution {
	
	public int reverse(int x) {
           String toReverse = ""+x;
           System.out.println("rev " + toReverse );
           String newString = "";
           for (int i=toReverse.length()-1; i>=0;i--){
        	if(toReverse.charAt(i) == '-'){
        		newString = "-" + newString;
        		break;
        	}
        	
        	newString += Character.toString(toReverse.charAt(i));
         }
          System.out.println("newString " + newString);
          return Integer.parseInt(newString);
      }
	
	public static void main(String[] args) {
		Solution sol = new Solution();
		sol.reverse(-1211);
	}
}

[Karthik Shiraly]

Do they restrict inputs only to decimal integers?

Also, what output does it expect? That the number is printed on console?

[Liutauras Vilda]

Your subject says "Reversing an integer". At the moment you're reversing String. Maybe this is a problem.
Try to print out numbers in reverse way by using modulus operator.

[Ahsan Bagwan]

Reversing the string converted from integer might be the problem. Thanks.