This week's giveaway is in the Java/Jakarta EE forum. We're giving away four copies of Java EE 8 High Performance and have Romain Manni-Bucau on-line! See I know it looks like Arrays.sort(T, Comparator<? super T>) is only good for a 1-dimensional array but, as Campbell says, ALL Java arrays are 1-dimensional, so a Comparable is simply an array of Comparables.
Thus, in your case, 'T' is Comparable - although the 'Comparable' is actually a red herring, since you don't need it to sort your outer array.
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