Char to Integer

[Molayo Decker]

Hi
Am try to convert a Char Char A = 'F'; to an Integer without Changing 'F' to a numeric value. Then Set it at something like list.set(4, A). Is this possible?

[Paweł Baczyński]

Molayo Decker wrote:Hi
Am try to convert a Char Char A = 'F'; to an Integer without Changing 'F' to a numeric value. Then Set it at something like list.set(4, A). Is this possible?

What do you mean by this? An integer IS a numerical value. By the way, so is char.

[Molayo Decker]

Am writing a code to replace all numbers in an array that are divisible by another number to be replaced by F or B

So if 3 is divisible by 3 replace 3 in the array {1,2,F,4,5,6,7}. Am trying to set 3 to F by using the set method but it only takes two integers or two strings. set (int, String)

[Keith Lynn]

You mean the terms array and list. If you're using java.util.List, what type of object are you storing in it?

[Molayo Decker]

I am storing numbers in my ArrayList

public static void main (String[] args) throws IOException {
       BufferedReader buffer = new BufferedReader(new FileReader("number.txt"));
       ArrayList<Integer> list = new ArrayList<Integer>();
       Collections.addAll(list, 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15);
       String line;
        while ((line = buffer.readLine()) != null) {
            line = line.trim(); 
            String[] word = line.split(";");
            
            int x = Integer.parseInt(word[0]);
            int y = Integer.parseInt(word[1]);
            int xy = Integer.parseInt(word[2]);
            System.out.println("This the positive integer"+ word[0] );
            System.out.println("This the array"+ list.get(3));
            double result = ( list.get(4)% x);
            System.out.println(result);
		
			//System.out.println(list);
            if (result == 0) {
		  char a = 'F';
                  int F = a;
		   list.set(0, F);
                  System.out.println(list);		   		         
 				        
			}

[Campbell Ritchie]

Molayo Decker wrote:. . .

// ...
    if (result == 0) {
        char a = 'F';
        int F = a;
        list.set(0, F);
    }
// ...

Ouch! What dreadful variable names. Try
myList.set(0, (int)'F');
If you have a List<Integer>, you can put ints into it and they will undergo boxing conversion. You cannot (I think) put chars directly because they cannot undergo widening (=cast to int) and boxing conversion together. If you cast it to an int, then you only need boxing conversion and that can be done automatically.

[Paweł Baczyński]

What about
myList.set(0, +'F');
instead of
myList.set(0, (int)'F');

I have never seen + operator used in such way.
I don't know if the confusion is worth saving few keystrokes.

What do you think?

[Campbell Ritchie]

Now that is a first. I have never seen a possible use for the unary plus operator but I think you have got one there. Well done Paweł.

[salvin francis]

Paweł Baczyński wrote:
I have never seen + operator used in such way.

+1 For creativity

[Campbell Ritchie]

Since this isn't the “beginning” forum, at least we can be confident that everybody reading it knows what the unary plus operator does.

Can't we???‍???

[Jesper de Jong]

Note that a character such as 'F' is not an Integer, so you cannot store it in a list that can only hold Integer objects.

[Tim Cooke]

salvin francis wrote:+1 For creativity

49 for creativity .... .... +'1' .... get it? .... get it?

I'll get my coat.