Problem with conversion int to char as ASCII value

[Viktor Iurkov]

Hello everyone!
Asking for some help because i'm completely stuck on line #11. I hve no idea how to convert int to char, for example int 10 to char '10'.

 public String stringConverter (String s)
    {
        StringBuilder str = new StringBuilder(s);
        for (int i =0; i<s.length(); i++)
        {

            if (s.toLowerCase().charAt(i) == 'a' || s.toLowerCase().charAt(i) == 'i' ||
                     s.toLowerCase().charAt(i) == 'e' || s.toLowerCase().charAt(i) == 'o' ||
                    s.toLowerCase().charAt(i) == 'u')
            {
                [b]char b = Character.forDigit(i+1, s.length());[/b] // this prints ' ' symbol when i > 10. I don't know how to convert (for ex) int i =10 to char b == '10'
                System.out.println(b);
                str.setCharAt(i, b);
                //str.setCharAt(i,Integer.toString(i+1).charAt(0)); // convertation is wrong on digits >10
            }
        }
        return str.toString();

[Knute Snortum]

If you look at an ASCII chart you will see that ASCII '0' is dec 48. So adding 48 to 0 will give you '0'. Since chars are ints (kinda) you can add to them like a number.