Rotate a cube

[Debarun Mukherjee]

How can I rotate a cube about 1 of its edges?

[Les Morgan]

Using Trigonometry, specifically the Pythagorean Theorem-- h^2 = x^2 + y^2, so the square root of x^2 + y^2 gives you the length from your set vertices.

X = cos(A), Y = sin(A) where A is your rotational angle.

[Piet Souris]

Rotating a cube around one of its edges is a rotation in 3D,
so that is not an easy thing to do.

I don't know much about JavaFX, but a quick look at the API
gives that you can set a rotation axis to a Node, and a Cube
is a Box, which is a sub-subclass of Node, if I understand correctly.

Have you looked at the API's of JavaFx?

[Jan Daermann]

Piet is right, create box ("yourBox"). Then
- set axis via yourBox.setRotationAxis(edge of box parameters) and
- rotate it via yourBox.setRotate(degrees)

[Debarun Mukherjee]

Yeah I checked them. I need to rotate the cube by setting the pivot of rotation at one of the corners of the cube. But I cant determine the coordinates of the cube. How to get that? I actually need to rotate 4 cubes placed side by side about the centre of the system. That's why I need to get the coordinates of the common corners of the 4 cubes and set each of their pivot of rotation to that coordinate. How can I figure that centre ?

[Debarun Mukherjee]

set axis via yourBox.setRotationAxis(edge of box parameters)

How to get the edge of box parameters ?

[Debarun Mukherjee]

Okay yeah I understood the trigonometric solution ! Thanks