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# Infinite loop, Question 9 on page 96 (Java OCA 8 Programmer I Study Guide, Sybex)

Jason Attin
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Posts: 232
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Hi guys, on page 96 of the OCA book, question 9, not sure I understand that.

This they say, generates an infinite loop. Not sure why though, as the variable i is incremented with i=i++. I mean i++ means we add 1 to i each time it executes...

Ganesh Patekar
Bartender
Posts: 696
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Yes i++ does increment  i by 1 but the previous value of i i.e. 0 which was pushed on operand stack is assigned to i so again i becomes 0. This is why i always remains 0 and loop repeats infinitely.
You can refer this post

Jason Attin
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Posts: 232
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thanks. Not sure I understand, sorry. I had a look at the other post and I think it's still not clear to me. I tried with a similar example, but I still don't get it.

i is still 9 after the assignment. So i starts off with a value of 9. Then we have which we can write as I would have thought...

Ganesh Patekar
Bartender
Posts: 696
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JVM uses operand stack for asigning values to local variables and these operations. It keeps array of these local variables.
Here int i = 9 means first int 9 value is pushed on operand stack then pops 9 value from operand stack and assign It to i.

i = i++; doesn't mean 9 = 9+1, in general we can see It like i  = 9 + 1; because at left side of = we need something to store the result so here i is a varaible Or we can say a storage to store the result so It can't be a digit.

Here i = i++; might look i = 9 + 1 but JVM first pushes the value of i i.e. 9 on operand stack then ++ is executed which directly increments value of local variable i by 1 so i becomes 10 now, but after that JVM pops value which was on operand stack i.e. 9 and assigns to i so again i becomes 9.

Daniel Cox
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Posts: 147
7
In this code

there are 2 operations in the expression i = i++ and the ++ operator will operate before the = operator since it has a higher precedence.

Operation 1 (++ operator)
i++ will do 2 things:
• i++ evaluates to 9 (at this point i = i++ becomes i = 9 but the i = 9 assignment operation is not executed yet)
• i++ increments i by 1 (at this point, a separate i = 10 assignment operation is executed and a value of 10 is assigned to i)

• Operation 2 (= operator)
The assignment operation i = 9 is executed and a value of 9 is assigned to i

Roel De Nijs
Sheriff
Posts: 10662
144
Jason Attin wrote:Not sure why though, as the variable i is incremented with i=i++. I mean i++ means we add 1 to i each time it executes...

In this topic you'll find an explanation for exactly the same question. And in this topic you'll find an extensive discussion with lots of code examples. Both are definitely worth reading!

Hope it helps!
Kind regards,
Roel

Jason Attin
Ranch Hand
Posts: 232
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thanks for the explanation and links, now it's clear. And the funny thing is that now that it's clear, it's so obvious!
thanks