Split Head Scratcher

[Dennis Putnam]

I guess I need some new eyes as I must be missing something stupid since this is so trivial.

System.out.println(version);
String[] v=version.split(".");
System.out.println(Arrays.toString(v));

The output of this is:
11.0.2.1
[]

How is that possible? Even if there were no '.' in the string it should contain the entire string as the first and only element of the array, right?

[Henry Wong]

The split() method takes a regular expression. A DOT in regex is any character. So, in your example, every character in the string is a delimiter.

Additionally, you are using the version of the split() method, that deletes trailing blank matches. And since every character is a delimiter, then every match is a zero-length blank match.

Henry

[Dennis Putnam]

Arrgh! I knew it was something stupid. Thanks.

String[] v=version.split("\\.");

[Junilu Lacar]

You need to escape the "." if you want it to be taken as the literal character.  Try split("\\.")

EDIT: Looks like you already did.