• Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other all forums
this forum made possible by our volunteer staff, including ...
Marshals:
  • Liutauras Vilda
  • Campbell Ritchie
  • Tim Cooke
  • Bear Bibeault
  • Devaka Cooray
Sheriffs:
  • Jeanne Boyarsky
  • Knute Snortum
  • Junilu Lacar
Saloon Keepers:
  • Tim Moores
  • Ganesh Patekar
  • Stephan van Hulst
  • Pete Letkeman
  • Carey Brown
Bartenders:
  • Tim Holloway
  • Ron McLeod
  • Vijitha Kumara

Handling exceptions  RSS feed

 
Ranch Hand
Posts: 192
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
This is the code: It will compile but will throw AnotherException when run.

Explanation
m2() throws NewException, which is not caught anywhere. But before exiting out of the main method, finally must be executed. Since finally throw AnotherException (due to a call to m3() ), the NewException thrown in the try block ( due to call to m2() ) is ignored and AnotherException is thrown from the main method.

I thought the exception has to be caught; m2() throws NewException, which is not caught anywhere. I would kindly ask for a clarification.
 
Saloon Keeper
Posts: 9239
177
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
The exception is propagated upward. The main() method can do this because it declares that it can throw Exception.
 
Don't get me started about those stupid light bulbs.
  • Post Reply Bookmark Topic Watch Topic
  • New Topic
Boost this thread!