stackoverflow error

[Luanrkiran kumar]

class Bird {
Bird a=new Bird();
 
}
public class Peacock extends Bird {

public static void main(String[] args) {

	new Bird();
	

}
}

I just want to know how the  above code works..and what to do to get rid of stack overflow error.

[Niall Kev]

Issue appears to be with :

Bird a=new Bird();

[Luanrkiran kumar]

I just wanted to know how it works.

[Dave Tolls]

Let's step through it.

When you execute this code, the first thing that the code in main() does is create a new Bird instance.

Now, when a Bird instance is created it has a Bird attribute, which is declared and instantiated at the same time (line 2).
So, main creates a Bird instance, which itself creates a Bird instance...which itself creates a Bird instance...and so on.

[Daniele Barell]

Hi Luanrkiran kumar.

Luanrkiran kumar wrote:

class Bird {
Bird a=new Bird();
 
}
public class Peacock extends Bird {

public static void main(String[] args) {

	new Bird();
	

}
}

I just want to know how the  above code works..and what to do to get rid of stack overflow error.

- a is an isntance of Bird, which is instantiated at construction of Bird object
- When you construct a Bird object a is instantiated calling the Bird constructor another time.
- So every time you call new Bird(), a is created calling new Bird() again.
- So for Bird bird = new Bird(), This code cicles endlessly creating an abject like bird.a.a.a.a.a.a.a.a ....

To escape this code you can change the code in various way.
One option I suggest is to set the variable a static

[Luanrkiran kumar]

thank you, it was helpful.