Thread run() method

[Santosh Kumar Nayak]

class MyThread extends Thread {
	MyThread(){ System.out.println("MyThread"); }
	
public void run(){ System.out.println("Bar "); }
public void run(String s){ System.out.println(" baz "); }
}


public class T3 {
 public static void main(String args[]){
 Thread t = new MyThread(){
	 public void run(){  System.out.println("foo"); }
 };	
  t.start();
   }
}

Output for 1st case:
MyThread
foo


But the Line 12 code is changed to

public void run(String s){  System.out.println("foo"); }

Ouput for 2nd case :
MyThread
Bar


What I want to understand is about the 2nd case

[Paweł Baczyński]

Thread t = new MyThread(){
     public void run(){  System.out.println("foo"); }
 };

This is an anonymous class that extends MyThread and overrides its run() method.
When you start this thread the overriden method is executed and it prints "foo".

Thread t = new MyThread(){
     public void run(String s){  System.out.println("foo"); }
 };

This is an anonymous class that extends MyThread and does not override its run() method. The run() method is overloaded instead.
When you start this thread the run() method from MyThread is executed and it prints "Bar".

[Prasad Saya]

Note that when a thread is started (using thread.start()) its run() method is executed. In the following code:

Thread t = new MyThread(); // creates a thread object
t.start(); // runs the code in the run() method, not the run(String) method.

1st case:

The code on line 12 overrides the MyThread class's run() method. Hence the result: foo
Overrides method: lets say it replaces the code within the method, in this case.


2nd case:

The run() method is not overridden, in this case. Hence the result from the original run method: Bar

Having the line public void run(String s) {  System.out.println("foo"); has no consequence in both cases, in this example.