Method Overloading is a feature that allows a class to have more than one method having the same name, if their argument lists are different. It is similar to constructor overloading in Java, that allows a class to have more than one constructor having different argument lists.
here are two ways to overload the method in java
By changing number of arguments
By changing the data type
In java, Method Overloading is not possible by changing the return type of the method only.
1) Method Overloading: changing no. of arguments
In this example, we have created two methods, first add() method performs addition of two numbers and second add method performs addition of three numbers.
In this example, we are creating static methods so that we don't need to create instance for calling methods.
class Adder{
static int add(int a,int b){return a+b;}
static int add(int a,int b,int c){return a+b+c;}
}
class TestOverloading1{
public static void main(String[] args){
System.out.println(Adder.add(11,11));
System.out.println(Adder.add(11,11,11));
}}
Test it Now
Output:
22
33
2) Method Overloading: changing data type of arguments
In this example, we have created two methods that differs in data type. The first add method receives two integer arguments and second add method receives two double arguments.
class Adder{
static int add(int a, int b){return a+b;}
static double add(double a, double b){return a+b;}
}
class TestOverloading2{
public static void main(String[] args){
System.out.println(Adder.add(11,11));
System.out.println(Adder.add(12.3,12.6));
}}
Test it Now
Output:
22
24.9
Q) Why Method Overloading is not possible by changing the return type of method only?
In java, method overloading is not possible by changing the return type of the method only because of ambiguity. Let's see how ambiguity may occur:
class Adder{
static int add(int a,int b){return a+b;}
static double add(int a,int b){return a+b;}
}
class TestOverloading3{
public static void main(String[] args){
System.out.println(Adder.add(11,11));//ambiguity
}}
Test it Now
Output:
Compile Time Error: method add(int,int) is already defined in class Adder
System.out.println(Adder.add(11,11)); //Here, how can java determine which sum() method should be called?
Note: Compile Time Error is better than Run Time Error. So, java compiler renders compiler time error if you declare the same method having same parameters.
Can we overload java main() method?
Yes, by method overloading. You can have any number of main methods in a class by method overloading. But JVM calls main() method which receives string array as arguments only. Let's see the simple example:
class TestOverloading4{
public static void main(String[] args){System.out.println("main with String[]");}
public static void main(String args){System.out.println("main with String");}
public static void main(){System.out.println("main without args");}
}
Test it Now
Output:
main with String[]