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Fortran 4 related. What would the act of creating a new record look like in binary

 
Greenhorn
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A FORTRAN 4 program was written this way for 7049 computer when creating a new record.I am dealing with 36 bit words.
WRITE(8)  NTYPE,  NREC,  MM,  NN, ...plus 3 other items separated by commas not mentioned because unrelated to question, to equal 8
resulted in a binary file that looks like this when written as octals:
000511000000 000000000001 000000000001 000000000005 000000000200 ...plus 3 other 36bit words displayed as octals to equal 8 not mentioned because unrelated to question.  The last 4 words when converted to decimal are 1,1,5 and 128 which was expected. The first word is the mystery.

Now the Question:
Why might WRITE(8) generate a "000511000000"  in the beginning of a new record?
When I convert it to a decimal or just 000101001001000000 it seems to have no particular significance.
To those who understand fortran do you know what "000511000000" might mean at the start of creating a new record when looked at in the binary or in this case octal?  Maybe its just a marker of some type thats common? If so are their other marker types I should know about when examining binary files?
thanks
 
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