Spring MVC: web.xml and servlet-mapping

[Bilal Ghayad]

Hello;

I wrote my spring mvc application to work based on the http://localhost:8080 is the root directory, and every thing is working fine.

So my web.xml was having the following servlet-mapping settings:

	<servlet-mapping>
		<servlet-name>appServlet</servlet-name>
		<url-pattern>/</url-pattern>
	</servlet-mapping>

But now when I came to the deployment, I am deploying the application under the directory NEP_WF_CLIENT, so the root url will be: http://ip_address:8080/NEP_WF_CLIENT instead of http://ip_address:8080, so what is the best modification that I have to do it?

I know that I have to change the servlet-mapping to become:

	<servlet-mapping>
		<servlet-name>appServlet</servlet-name>
		<url-pattern>/NEP_WF_CLIENT/*</url-pattern>
	</servlet-mapping>

But, that will require to do too many changes (for each controller, I have to do the change in the mapping and in the returning), and that is a big effort just because I placed the application under new directory.
What is the solution to avoid having complete changes? I am sure there is a way using prefix and suffex (adding or removing) that will resolve the problem.

Appreciate the kindly help.
Regards
Bilal

[Miroslav Lehotsky]

You don't need to change anything. Deployment location changes context path, but 'url-pattern' is independent and is appended after context path. So, if you deploy your app under ROOT directory, you can hit endpoint with url-pattern = '/' at http://ip_address:8080/, if you deploy your app under NEP_WF_CLIENT directory, you can hit endpoint with url-pattern = '/' at http://ip_address:8080/NEP_WF_CLIENT/. I speak from my experience with Tomcat, not sure if that generally applies to all web servers.