Java programming.

[Basit Raza]

Question -

You are given an array a with N integers and an integer K. Output the smallest number in array which occurs exactly K times in an array. There will always be a number that is occurring K times.


Sample Input
5
2 2 1 3 1
2

Sample Output
1

MY code -

import java.io.*;
import java.util.Scanner;

public class Smallno {

    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        int N, K, i;
        N = sc.nextInt();
        int arr [] = new int[N];
        int freq [] = new int[10];
        
        for (i=0; i<N; i++){
            arr[i] = sc.nextInt();
        }
        
        K = sc.nextInt();
        
        for(i=0; i<N; i++){
            freq[arr[i]]++;
        }
        
        for(i=0; i<10; i++){
            if(freq[i] == K){
                System.out.println(i);
                break;
            }
        }
    }
} 

why does my code says runtime error?

[Randy Tong]

Please post the full stacktrace

[Jesse Duncan]

Welcome to the Ranch!

I formatted your code for you. Doesn't that make it much easier to see what is going on?

[Campbell Ritchie]

Welcome again

Please always put spaces between (non‑unary) operators and operands: not for (i=0; i<N; i++) ... please but for (i = 0; i < N; i++) ... No space in i++ however. Don't put constants in the for header. Write myArray.length instead. >
I like your counting technique, but what makes you think there will not bemore than ten different values?