If you have an expression (exp1, exp2) then yes, both exp1 and exp2 are evaluated. But the value of exp1 is thrown away; the result of (exp1, exp2) is exp2. Does that help?
If you have an expression (exp1, exp2) then yes, both exp1 and exp2 are evaluated. But the value of exp1 is thrown away; the result of (exp1, exp2) is exp2. Does that help?
Cheers
John
Thanks a lot... I've been thinking hard just to make sense of it...
My favorite is a chocolate cupcake with white frosting and tiny ad sprinkles.