Problems with JSON Array can't become String

[Marcus Vinícius]

Hello,

I'm making this APP for my company, but I've never used JSON with Java before, so I'm kinda lost here. After watching some tutorials, I made this function

private void jsonParse(String url) {
        JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                try {
                    JSONArray jsonArray = response.getJSONArray("nome");

                    for (int i = 0; i < jsonArray.length(); i++) {
                        JSONObject nome = jsonArray.getJSONObject(i);
                        String name = nome.getString("nome");

                        razao.append(name);
                        razao.setText(name);
                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                    Toast.makeText(getActivity(), "CNPJ Inválido ! ", Toast.LENGTH_SHORT).show();
                }
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError erro) {
                erro.printStackTrace();
            }
        });

        mQueue.add(request);
    }

But the response from the URL that I get is a JSON with no name,

{
 "atividade_principal": [
   {
     "text": "Portais, provedores de conteúdo e outros serviços de informação na internet",
     "code": "63.19-4-00"
   }
 ],
 "data_situacao": "01/09/2004",
 "complemento": "ANDAR 17A20 TSUL 2 17A20",
 "tipo": "MATRIZ",
 "nome": "GOOGLE BRASIL INTERNET LTDA.", //I need this part

Can someone help me, please ? This array worked like a charm, how to get "nome" from this JSON ?

 
JSONArray jsonArray = response.getJSONArray("atividade_principal");
for (int i = 0; i < jsonArray.length(); i++) {
     JSONObject nome = jsonArray.getJSONObject(i);
     String name = nome.getString("code");

If anyone needs the whole JSON: https://www.receitaws.com.br/v1/cnpj/06990590000123

That's my Log:
org.json.JSONException: Value GOOGLE BRASIL INTERNET LTDA at nome of type java.lang.String cannot be converted to JSONArray

I thank you for the help, my native forums aren't helping me

[Roland Mueller]

Marcus Vinícius wrote:Hello,

I'm making this APP for my company, but I've never used JSON with Java before, so I'm kinda lost here. After watching some tutorials, I made this function

private void jsonParse(String url) {
        JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                try {
                    JSONArray jsonArray = response.getJSONArray("nome");
    }

That's my Log:
org.json.JSONException: Value GOOGLE BRASIL INTERNET LTDA at nome of type java.lang.String cannot be converted to JSONArray

The JSON string from the URL shows that you have an JSON object that is not an array. As immediate child there is the JSON value "nome" which has value "GOOGLE BRASIL INTERNET LTDA." and is definitely no array as the error message in the log says.

Probably, you should only retrieve the object with key "nome" and return it. following code is an untested guess:

    JSONObject jsonObjectToReturn  =Json.createObjectBuilder().add("nome", response.getJSONString("nome") );
    ...

[Marcus Vinícius]

Roland Mueller wrote:

Marcus Vinícius wrote:Hello,

I'm making this APP for my company, but I've never used JSON with Java before, so I'm kinda lost here. After watching some tutorials, I made this function

private void jsonParse(String url) {
        JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                try {
                    JSONArray jsonArray = response.getJSONArray("nome");
    }

That's my Log:
org.json.JSONException: Value GOOGLE BRASIL INTERNET LTDA at nome of type java.lang.String cannot be converted to JSONArray

The JSON string from the URL shows that you have an JSON object that is not an array. As immediate child there is the JSON value "nome" which has value "GOOGLE BRASIL INTERNET LTDA." and is definitely no array as the error message in the log says.

Probably, you should only retrieve the object with key "nome" and return it. following code is an untested guess:

    JSONObject jsonObjectToReturn  =Json.createObjectBuilder().add("nome", response.getJSONString("nome") );
    ...

Thanks for the reply, but how would I use it in the function ? I did some search and Json is a library from Java and when I tried to use it in Android it didn't work  

[Marcus Vinícius]

Guys, I found the solution.

In this case, the JSON that I'm looking isn't an array, so I already started wrong.

After some search and help on the web, I finished it.

private void jsonParse(String url) {
        JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {

            String jsonr; 
            String jsonc; 
            @Override
            public void onResponse(JSONObject response) {
                try {
                    jsonr = response.getString("nome"); //no .getJSONObject
                    jsonc = response.getString("cnpj"); //no .getJSONObject

                    razao.setText(jsonr);
                    cnpj.setText(jsonc);

                } catch (JSONException e) {
                    e.printStackTrace();
                    Toast.makeText(getActivity(), "CNPJ Inválido ! ", Toast.LENGTH_SHORT).show();
                    razao.setText("");
                }
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError erro) {
                erro.printStackTrace();
                Toast.makeText(getActivity(), "CNPJ Inválido ! ", Toast.LENGTH_SHORT).show();
                razao.setText("");
            }
        });

        mQueue.add(request);
    }

And this applies to any other String in JSON, I could make a .getString("stringname"); for each String in JSON with no worries !

Thank you again !