Remove one or two middle letters from a word

[Peter Kennedy]

I need the shortest possible c++ code to solve this problem, with an explanation of each line of code. Here is the task: the word is given. If its length is odd, then delete the middle letter, otherwise - two middle letters.

I found solutions to this task on the Internet, but the solutions are huge and without explanation, and I need to learn it and it should be as short as possible in c++ code with an explanation of each line of code. So I found solutions:
#include <iostream> #include <cstring> int main(){ char str[1000];; std::cin.getline(str, 1000); int n = strlen(str); int ser = n / 2 - (n%2==0), i = ser, shift = 1 + (n%2==0); // середина и конец    for (i = ser; i != n - shift; i++) str[i] = str[i + shift]; str[i] = '\0'; std::cout << str << std::endl; }

[Stephan van Hulst]

Welcome to CodeRanch!

Finding ready solutions on the internet won't do. Instead, tell us how YOU would solve the problem. What are you stuck on?

[Campbell Ritchie]

Welcome to the Ranch (again).

Peter Kennedy wrote:. . .
. . . - (n%2==0) . . .

Please tell us where you found that. Did they explain what that bit of code does? Did they tell you it is an abomination against the conventions of good programming? There are all sorts of things on the Internet and it is difficult to tell whether you have found something very good or very bad.

[John Matthews]

I would have thought your best bet would be a single memmove(), no loops. Just (obviously) need to work out its arguments, but without actually trying it, I wouldn't have thought that was too difficult...

[John Matthews]

Corrected the indentation of the original post:
#include <iostream> #include <cstring> int main(){  char str[1000];;  std::cin.getline(str, 1000);  int n = strlen(str);  int ser = n / 2 - (n%2==0), i = ser, shift = 1 + (n%2==0); // середина и конец  for (i = ser; i != n - shift; i++)    str[i] = str[i + shift];  str[i] = '\0';  std::cout << str << std::endl; }

[Peter Kennedy]

Stephan van Hulst wrote:Welcome to CodeRanch!

Finding ready solutions on the internet won't do. Instead, tell us how YOU would solve the problem. What are you stuck on?

I wanted to ask you for help, I myself know C++ terribly.

[Peter Kennedy]

I found the code on some site, I do not remember exactly which one. Code snippet, no. No.

[Peter Kennedy]

Peter Kennedy wrote:

Peter Kennedy wrote:I need the shortest possible c++ code to solve this problem, with an explanation of each line of code. Here is the task: the word is given. If its length is odd, then delete the middle letter, otherwise - two middle letters.

I found solutions to this task on the Internet, but the solutions are huge and without explanation, and I need to learn it and it should be as short as possible in c++ code with an explanation of each line of code. So I found solutions:
#include <iostream> #include <cstring> int main(){ char str[1000];; std::cin.getline(str, 1000); int n = strlen(str); int ser = n / 2 - (n%2==0), i = ser, shift = 1 + (n%2==0);    for (i = ser; i != n - shift; i++) str[i] = str[i + shift]; str[i] = '\0'; std::cout << str << std::endl; }

And why fix the otsup, I asked for a solution to this problem, I need the shortest possible C ++ code with an explanation of each line of code for that task.

[Paul Clapham]

Peter Kennedy wrote:I asked for a solution to this problem, I need the shortest possible C ++ code with an explanation of each line of code for that task.

What would you need that for?

[Campbell Ritchie]

Peter Kennedy wrote:I found the code on some site, I do not remember exactly which one. . . . .

Shame. You could have blacklisted it.

Please don't push quote to reply. Push reply. Quotes often add nothing to the discussion, and in your post you had my words outside the quoted area.

[Peter Kennedy]

Paul Clapham , I need to write this code in college.

[Campbell Ritchie]

Yes, you have to write it yourself.

[Peter Kennedy]

Campbell Ritchie,and why I turned to this site then, I myself don’t know C++ well.

[Campbell Ritchie]

Start by turning your computer off. It is getting in your way. Then write some words on paper; you need an eraser too because you will have to destroy the evidencecorrect any mistakes. Go through the individual letters and write out the logic for copying them to a new location or not copying them.
Remember: if you are using a char[] for a word with n letters, you will need space for n + 1 letters because of the null character at the end.