I have an application, SampleApp, under webapps directory in tomcat-4.1.24 environment. I am able to access my app (which is just one servlet) as: http://localhost:8080/SampleApp/servlet/SampleServlet My confusion is about: 1) Why should I use http://localhost:8080/SampleApp/servlet/SampleServlet to access the servlet instead of using http://localhost:8080/SampleApp/SampleServlet (i.e. without /servlet in the URL)? Where is this configured? How to make this work without /servlet in the URL? 2) Looks like the web.xml file for my app (in <whatever>/webapps/SampleApp/WEB-INF/web.xml) is not being read. For example, I have the following in web.xml: <servlet> <servlet-name>SampleServlet</servlet-name> <servlet-class>SampleServlet</servlet-class> <run-as> <description>Security role for anonymous access</description> <role-name>tomcat</role-name> </run-as> </servlet> When I call String myServletName = getServletConfig().getServletName(); it throws an exception instead of getting the name of the servlet from web.xml. I have tried shutting down tomcat server, adding all kinds of extraneous stuff to web.xml, rebooting the machine, etc. Problem still exists. What am I doing wrong here? Thanks in advance for your help.
Thanks, Oliver...confusion 1) is cleared. 2) is still a problem.
Post by:William Brogden
When you address a servet using the /servlet/yourservlet approach, it is the invoker servlet that loads the class and runs it. The use of invoker causes all sorts of bizarre problems - you would be much better off to get your web.xml set up correctly so that you can address it directly and the servlet engine sees your servlet as a real web application. Bill