Hi,
I am trying out
servlet example in
Tomcat 5.0.27
I created a simple TestServlet servlet. Compiled and pasted the class file in <tomcathome>\webapps\ROOT\WEB-INF\classes\TestServlet.
Then I modifed the web.xml Below you can find the part of web.xml
<servlet>
<servlet-name>TestServlet</servlet-name>
<servlet-class>TestServlet</servlet-class>
</servlet>
<servlet>
<servlet-name>org.apache.jsp.index_jsp</servlet-name>
<servlet-class>org.apache.jsp.index_jsp</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>org.apache.jsp.index_jsp</servlet-name>
<url-pattern>/index.jsp</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>TestServlet</servlet-name>
<url-pattern>/test</url-pattern>
</servlet-mapping>
When I tried to open the servlet
http://localhost:18080/test I am getting 404 Status error
however if I replace url-patter of TestServlet as
<url-pattern>index.jsp</url-patter>
and try like
http://localhost:18080/ I can see the TestServlet's output.
Please let me know what configuration I need to make to resolve the issue with calling the servlet directly