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I have created one application folder as

C:\Program Files\Apache Software Foundation\Tomcat 4.1\webapps\oneapp

and saved one html file in it like this:

C:\Program Files\Apache Software Foundation\Tomcat 4.1\webapps\oneapp\form1.html

and tried running tomcat like this:


What I m getting is :

HTTP Status 404 - /Beer/form.html

type Status report

message /Beer/form.html

description The requested resource (/Beer/form.html) is not available.
Apache Tomcat/4.1.34


when i m saving same form1.html as index.html in ROOT directory,it is working fine on running like this :


Can somebody tell me why it is happening.
[ September 16, 2007: Message edited by: Bear Bibeault ]
hemant chaudhary
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One more doubt

when i m trying to access index file like this :

http://localhost:8080...its working.

but when i m trying to access it like this :


it is again giving 404 error

Please enlighten me.
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A web application has four parts:

A public directory
A WEB-INF/web.xml file
A WEB-INF/classes directory
A WEB-INF/lib directory

The public area is the root of the application, excluding the WEB-INF directory. In your case it's located at C:\Program Files\Apache Software Foundation\Tomcat 4.1\webapps\ROOT

If you place form1.html there http://localhost:8080\form1.html will serve it.

You can go ahead and create the directory
C:\Program Files\Apache Software Foundation\Tomcat 4.1\webapps\ROOT\beer

And place there the form.html file.

http://localhost:8080\beer\form.html will serve it.

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