Luciano Mantuaneli

By the way, Thread.stop is depracated:
http://java.sun.com/j2se/1.4.2/docs/guide/misc/threadPrimitiveDeprecation.html

A simple way to have some control if the finally is executed or not - its content, at least - is to use a boolean control variable:
Connection con = SomeJDBCDriver.getConnection(strConnection); boolean closed = false; try{ ... con.close(); closed = true; }catch(FooException fe){ ... }catch(BarException be){ ... }finally{ if(!closed){ con.rollback(); con.close(); closed = true; } }

I made this test and the instances seems to work independently...
public class CalendarTest { public static void main(String[] args) { SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss"); Calendar cal1 = new GregorianCalendar(2005, 01, 01); Calendar cal2 = new GregorianCalendar(2006, 01, 01); System.out.println("sdf.format(cal1.getTime()): " + sdf.format(cal1.getTime())); System.out.println("sdf.format(cal2.getTime()): " + sdf.format(cal2.getTime())); cal1.add(Calendar.MONTH, 2); System.out.println("After add 2 months to cal1"); System.out.println("sdf.format(cal1.getTime()): " + sdf.format(cal1.getTime())); System.out.println("sdf.format(cal2.getTime()): " + sdf.format(cal2.getTime())); } }

If you really want to do this:

Create an java.util.Properties object

Load your property file into the Properties object

Create an TreeMap object, passing to its constructor your Properties object

Use a simple for strategy to output the key-value pairs of the TreeMap objecto into a String object

write that String into your file

Have Fun!

I guess there is no such thing in Java...

If you don't bother in receive those convertions in a String format, you can use the Integer's methods:

toBinaryString(int)

toOctalString(int)

toHexalString(int)

However, if you declare an int variable and atribute a number prefixed with the zero digit, you assigning an actal value. The same happens for an hax value, if you prefix the number with "0x".

public class OctHexDecBin { public static void main(String[] args) { int value = 15; System.out.println(Integer.toBinaryString(value));; System.out.println(Integer.toOctalString(value)); System.out.println(Integer.toHexString(value)); value = 010; System.out.println(value); value = 0x10; System.out.println(value); } }

I guess thera are some misunderstanding here...
A Java compiler receive a .java file and "spits" a .class file. The .class file have the bytecode. So, the Java compiler transforme java text in bytecode text.
A JVM interprets the bytecode contained in the .class file to the OS/Machine for which that JVM has been created. A JVM for windows, interprets a .class to windows systems, etc.

Originally posted by Jesper Young:

Luciano, please don't post the complete solution - that way Jalli will not learn anything. Have you read the description of the beginner forum? It says:

Got it!

First, refere to the java.util.Arrays documentation
Then, if have questions about it, ask us here!
Have fun!

what syntax exactly you don't understand?

Originally posted by Keith Lynn:
Starting with JDK 1.4, the String class has a method called split() that will split the String into an array of tokens using a regex as delimiter.

This approach can be very tricky: Depending on your regex, you may have distorted values
[ December 04, 2006: Message edited by: Luciano Mantuaneli ]

It has to be pseudo code? Because I know a solution using features too specific of Java API. Can't see how to express it in pseudo code... Let me try:
countWords(str:String): long{ Establish a regex pattern that matches a word scan the text counting every match of your pattern return the counting }
If you want to see the code, let us know!

Although you don't posted how you try to print your result, I can guess you made it like this:
public static void main(String[] args) { double l_tot_link = 12.1666; DecimalFormat df = new DecimalFormat("###.##"); df.format(l_tot_link); System.out.println(l_tot_link); }
If you done something like that, you will have in your console the 12.1666 value indeed. You have to know that the format method don't modify the parameter.
Try something like this:
public static void main(String[] args) { double l_tot_link = 12.1666; DecimalFormat df = new DecimalFormat("###.##"); System.out.println(df.format(l_tot_link)); }

There is many approaches. I'll give you two.
1) If your String array is sorted, you can use the java.util.Arrays' binarySearch method:
int position = Arrays.binarySearch(myStringArray, myString);

2)You can use an temporary java.util.List object created from your array and use the indexOf method
int position = Arrays.asList(myStringArray).indexOf(myString);

Hope it heps you!

PS.: Note that, in both cases, if the position variable hava an negative value, it means that myString wasn't found in myStringArray array
[ December 04, 2006: Message edited by: Luciano Mantuaneli ]