Murthy Tanniru

Refer to https://docs.oracle.com/javase/tutorial/java/javaOO/methods.html

Here is the example. In the address class setAddress method is used to set zip and getZip() method returns zip.

public class Address { private String zip; public void setAddress(String zip) { this.zip = zip; } public String getZip() { return zip; } public static void main(String[] args) { Address addrss = new Address(); addrss.setAddress("78909"); addrss.getZip(); } }

Collections sort is the best way to do it. Here is the tutorial http://download.oracle.com/javase/tutorial/collections/interfaces/order.html

Refer to this API http://download.oracle.com/javaee/1.3/api/javax/servlet/http/HttpServlet.html

Refer to the database access tutorial http://download.oracle.com/javase/tutorial/jdbc/index.html

correct the code as below:

if (search_id == null || search_id.trim().length() == 0)

You can store the data in a cache. For this you can create a static class with static object.

If you want to use caching you can take a look at jboss cache which internally it uses jgroups

Look into java card technology
Java card technology

This may be similar case related to cluster. If the same data is added to the database with out proper keys(may be composite) the data gets added to the database and the insert will fail if try to add that is already inserted
[ October 23, 2008: Message edited by: Murthy Tanniru ]

Try using "rsync" or similar software for incremental file transfer to backup machine or local network to avoid network latency. And back up only the changes.

may be the scheduler in a different context

You can use caching which allows you to refresh cache once a day for any reason if the data changes

Correct the spelling mistake setProperty
<jsp:setProperty name="obj" property="name" value="joe" />
[ June 12, 2008: Message edited by: Murthy Tanniru ]

I agree. If you are using web app then use quartz else cron job will serve the purpose

use quartz http://www.opensymphony.com/quartz/