Michael Iaria

Oh!! Thanks!

In the Self-Test questions, the following code is listed for Chapter 7, question 16:

public class GeoCache { public static void main(String[] args) { String[] s = {"map", "pen", "marble", "key"}; Othello o = new Othello(); Arrays.sort(s, o); for(String s2 : s) { System.out.print(s2 + " "); } System.out.println(Arrays.binarySearch(s, "map")); } } static class Othello implements Comparator<String> { public int compare(String a, String b) { return b.compareTo(a); } }

This code doesn't compile (static modifier on class Othello), which is one of the choices (A). The answers are listed as D and G, claiming that there is actually output. Has anyone else encountered this?

Do you have to take them both? I want to take the latest and greatest, but I don't know if that means taking them both or not. Does anybody have any idea??

Do you have to take them both? I want to take the latest and greatest, but I don't know if that means taking them both or not. Does anybody have any idea??

Sure. I'm really talking about the SCJP 6 exam and the SCJP 6 Upgrade Exam. I'm definitely taking the SCJP 6 exam, but I don't understand the concept of an Upgrade Exam. Any thoughts?

I'm studying for the SCJP 5 exam (CX-310-065). I'm also interested in taking the upgrade exam (CX-310-066). Is it necessary to pass 310-065 before taking 310-066? Also, they mention that if you have already passed 310-065 that you can order 310-066 for a discounted price. Is anyone aware of what that price is?

Thanks for the reply. I have read elsewhere the HFSJ may be incomplete for the purpose of studying for the SCWCD 5 exam. Has anyone had any experience with the other study guide mentioned? Does anyone disagree that HFSJ may be incomplete, or does it do a good job in preparing one for the test?

I am currently looking into buying a study guide. I've seen the following:

Head First Servlets and JSP: Passing the Sun Certified Web Component Developer Exam (Brain-Friendly Guides) [ILLUSTRATED] (Paperback)
Sun Certified Web Component Developer Study Companion: SCWCD Java EE 5 (exams 310-083 and 310-084) (Paperback)

Any recommendations on either of these two or something different? I purchased the Sun Certified Java Programmer for Java 6 Study Guide from McGraw Hill, and I absolutely love it. They also have a SCWCD study guide, but it focuses on the 310-081 and 310-082 exams (the previous versions). What are your thoughts?

This is all making sense. What about this?

short s = 2; sifter(s); ... void sifter(int x) { ... } void sifter(Object o) { ... }

Which method will be invoked??
[ August 07, 2008: Message edited by: Michael Iaria ]

I have an intuitive grasp on why the output of the following code is what it is. The output is: -434. The study guide mentions that overloaded var-args methods are chosen last. Can someone please provide me with or point me to the hard and fast rules regarding which overloaded methods are invoked?

class A { //empty class } class B extends A { //empty class } class ComingThru { static String s = "-"; public static void main(String[] args) { A[] aa = new A[2]; B[] ba = new B[2]; sifter(aa); sifter(ba); sifter(7); System.out.println(s); } static void sifter(A[]... a2) { s += "1"; } static void sifter(B[]... b1) { s += "2"; } static void sifter(B[] b1) { s += "3"; } static void sifter(Object o) { s += "4"; } }

I'm studying for the SCJP exam, and I'm writing some sample code to further examine the self-test questions from the SCJP 6 Study Guide. I am confused as to why there is no ClassCastException when we say:

go2((Redwood) new Tree(), new Redwood());

Why am I allowed to downcast a Tree to a Redwood? I'm guessing it has something to do with the fact that the object is not referenced by a reference variable, but that's a shot in the dark. I am satisfied with the reason it happens when we say:

Redwood r2 = (Redwood)t1;

Any information would be appreciated:

class Redwood extends Tree { /** * @param args the command line arguments */ public static void main(String[] args) { new Redwood().go(); } void go() { go2(new Tree(), new Redwood()); go2((Redwood) new Tree(), new Redwood()); } void go2(Tree t1, Redwood r1) { Redwood r2 = (Redwood)t1; Tree t2 = (Tree)r1; } } class Tree { //empty class }