Soumya Ranjan Mohanty

i did exactly what you said and it's working fine. Thanks a lot joy b chakravarty .Can you please explain what was the mistake so that i can clear my doubt.

Again Thanks a lot.

I am not able to delete the corresponding one-to-one relation row using delete option of cascade. Here are the code for my class and Mappings.

Code For Employee.java Class.

public class Employee { private int eno; private String ename; PersonalDetails personalDetails; public int getEno() { return eno; } public void setEno(int eno) { this.eno = eno; } public String getEname() { return ename; } public void setEname(String ename) { this.ename = ename; } public PersonalDetails getPersonalDetails(){ return personalDetails; } public void setPersonalDetails(PersonalDetails pd){ personalDetails=pd; } }

Code for PersonalDetails.java Class
public class PersonalDetails { private int eno; private String fname,lname; Employee emp; public int getEno(){ return eno; } public void setEno(int eno){ this.eno=eno; } public String getFname(){ return fname; } public void setFname(String fname){ this.fname=fname; } public String getLname(){ return lname; } public void setLname(String lname){ this.lname=lname; } public void setEmp(Employee emp){ this.emp=emp; } public Employee getEmp(){ return emp; } }
mapping -- Employee.hbm.xml

<?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.titu.hibernate"> <class name="com.titu.hibernate.Employee"> <id name="eno" column="eno"> <generator class="foreign"> <param name="property">personalDetails</param> </generator> </id> <property name="ename" column="ename"></property> <one-to-one name="personalDetails" class="PersonalDetails" cascade="delete"></one-to-one> </class> </hibernate-mapping>

mapping- PersonalDetails.hbm.xml

<?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.titu.hibernate"> <class name="PersonalDetails"> <id name="eno" column="eno"> <generator class="increment"></generator> </id> <property name="fname" column="fname"></property> <property name="lname" column="lname"></property> <one-to-one name="emp" class="Employee" constrained="true"></one-to-one> </class> </hibernate-mapping>

When i delete any row from Employee table the Corresponding Foreign key row in PersonalDetails Table is not deleting. Please Help Me.

Thanks

What is persistencecontext and EntityManager ? what does it mean as

@PersistenceContext
EntityManager


I have Searched in google but couldn't find a appropriate solution.

Cameron Wallace McKenzie wrote:I'm currently looking for a distributor in India. Maybe in a few months?

Thanks for the interest!

-Cameron

Sir, did you find any distributor in India? i am very keen to buy your book. it's not available here.

Why can't we Use super in a static method. as super refers to the super class object then why can't we use super inside a static method. Please Explain.

Deepak Bala wrote:Yes. The equivalent would be an int array whose length is 0

Thank you.

class A { public static void main(String[] a){ int[] i={1,2,3}; A d=new A(); d.takeVar(); } public void takeVar(int... a){ for(int c:a) System.out.print(c+" "); } }


When i called takeVar() without any arguments , the program runs fine. Does it mean var-args can take 0 or more arguments?

Need References to Learn Java Annotation. How exactly it Works.

Can we Use super while creating a Generic class as.

public class Test<T super Dog>{ }

add is not allowed for ? extends but can be applied to ? extends super . C&B page 619.

import java.util.Scanner; class Tra { public static void main (String[] args) { int[] a={4,82,12,45,1,89,13,24,81,72,63,22}; int temp=0; for(int j=0;j<a.length;j++){ for(int i=0;i<a.length-1;i++){ if(a[i]>a[i+1]){ temp=a[i]; a[i]=a[i+1]; a[i+1]=temp; } } } for(int b:a){ System.out.print(b+" "); } System.out.println(); System.out.println("Enter the Element in the array a to Search"); Scanner sc=new Scanner(System.in); int c=sc.nextInt(); System.out.println("\n\n\n"); for(int k=0;k<a.length;k++){ if(a[k]==c){ System.out.println("Found "+c+" at position "+(k+1)); break; } } System.out.println("Couldn't Find"); } }
i am getting Couldn't Find even if i found the element. please help me. How to omit that message for found elements.

Congratulation. I am preparing for the Exam. How was the question Standard? is it as difficult as the questions in K & B book or the Master Exam ? or it was more difficult than that??

Question From Learn Key Master Exam.

Given Two Files
package xcom; public class Stuff { static int MY_CONSTANT = 5; static int doStuff(int x) {return (x++)*x; } }

and
import static xcom.Stuff.*; import static java.lang.System.out; class User { public static void main(String[] args) { new User().go(); } void go() { out.println(doStuff(MY_CONSTANT)); } }


This Code doesn't compile. please Someone help me to make this compile.

class Coffee { CoffeeSize cs; } public class CofTest { enum CoffeeSize { BIG,HUGE,OVERWHELMING } public static void main (String[] args) { CofTest ct=new CofTest(); Coffee c=new Coffee(); c.cs=CofTest.CoffeeSize.BIG; } }

Showing Compilation error as Incompatible type. Why?

import java.util.*; class ScanIn { public static void main(String[] args) { System.out.print("input: "); System.out.flush(); try { Scanner s = new Scanner(System.in); String token; do { token = s.findInLine(args[0]); System.out.println("found " + token); } while (token != null); } catch (Exception e) { System.out.println("scan exc"); } } }


Code is from K&B page no 501. i am not getting the output.

i execute: java ScanIn "\d\d";
input : 12aa675fks
got output as : found null