Josh Bern

I'm unsure how to make the text file appear in the dist folder besides the jar and how to write to it when the jar is run. I changed the path to this:

public static final String MY_FILE = "myfile.txt";

...and draged the text file to the dist folder by the jar. I type this in the command prompt:

C:\Documents and Settings\myName>java -jar "C:\Documents and Settings\myName\My Do
cuments\NetBeansProjects\myProject\dist\myjar.jar"


//When about to read in the file, not writing yet, this error materializes:
Exception in thread "main" java.lang.NullPointerException
at java.io.Reader.<init>(Unknown Source)
at java.io.InputStreamReader.<init>(Unknown Source)
at java.util.Scanner.<init>(Unknown Source)
at MyMain.main(QuestionMain.java:27)

Yo Wouter Out, thanks. Ok say I want to store simple text data inbetween runs, is my best option to store a text file in the same directory as the JAR? I'd love to bake it in somehow, but it's not worth it if it's too complicated.

Hi people, I'm new and this forum seems active!
I'm using NetBeans IDE and my directory structure looks like this:


I tried writing to a text file in the jar, can you folks see what's causing the exception in the command prompt when the following class is run in console like: java -jar "mypath/myjar.jar"? Thanks!
//class MyMain //Declaring fields public static final String MY_FILE = "res/myfile.txt"; //A filename of a text file in the "res" folder is a static field. //Entering main() to read in file and process InputStream s = MyMain.class.getClassLoader().getResourceAsStream(MY_FILE); //For reading the text file, so far so good, //it reads the txt from the res folder inside the jar when run from console. //Processing done, now I want to write to MY_FILE PrintStream ps = new PrintStream(new File(MyMain.class.getResource(MY_FILE).toURI())); //Tried this for opening the text resource in the jar, but at this line // the following exception is thrown when run from console (compiles ok)

Exception in thread "main" java.lang.IllegalArgumentException: URI is not hierarchical