Louis Cheung

all right,here's my code:
package demo; import java.util.Arrays; /** * * @author louis */ public class Test { private static final int[] GIVEN = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 }; public static void main(String[] args) { int[] Dest = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; int len = 10; go(GIVEN, Dest, len); System.out.println("THE RESULT IS:" + Arrays.toString(Dest)); } public static void go(int[] arrGiven, int[] arrDest, int len) { while (true) { find(arrGiven, arrDest, len); System.out.println(Arrays.toString(arrDest)); if (!check(arrGiven, arrDest, len)) { continue; } else { break; } } } public static void find(int[] arrGiven, int[] arrDest, int len) { for (int i = 0; i < len; i++) { int count = 0; for (int j = 0; j < len; j++) { if (arrGiven[i] == arrDest[j]) { count++; } } arrDest[i] = count; } } public static boolean check(int[] arrGiven, int[] arrDest, int len) { for (int i = 0; i < len; i++) { int count = 0; for (int j = 0; j < len; j++) { if (arrGiven[i] == arrDest[j]) { count++; } } if (arrDest[i] != count) { return false; } } return true; } } Console: [10, 0, 0, 0, 0, 0, 0, 0, 0, 0] [9, 0, 0, 0, 0, 0, 0, 0, 0, 1] [8, 1, 0, 0, 0, 0, 0, 0, 1, 0] [7, 2, 1, 0, 0, 0, 0, 1, 0, 0] [6, 2, 1, 0, 0, 0, 1, 0, 0, 0] THE RESULT IS:[6, 2, 1, 0, 0, 0, 1, 0, 0, 0]

Ryan McGuire wrote:Is [6,2,1,0,0,0,1,0,0,0] the only answer?

for now,that's true..
but if you change the input,there could be some other conditions..

it's like your answer just determines your answer...
you can show this character out in your code..

Paul Clapham wrote:Nope. If you look at the sequence [6,2,1,0,0,0,1,0,0,0] you will see that there are 6 0's, 2 1's, 1 2's, 0 3's, and so on. The business about [0,1,2,3,4,5,6,7,8,9] is just confusing and misleading, so ignore that.

[0,1,2,3,4,5,6,7,8,9]is the first line,
and the answer [6,2,1,0,0,0,1,0,0,0] is the second line.

Arjun Shastry wrote:so if input is
[11,44,99,11,22,55,66,77,10,99] output should be-
[1,5,2,0,2,2,2,2,0,4]? frequency of numbers from 0 to 9?

the input is constant[1,2,3,4,5,6,7,8,9]. if you choose other numbers like[11,44,99,11,22,55,66,77,10,99],
the 1 should be the times that 11 shows up in your answer,just as [1,5,2,0,2,2,2,2,0,4]. it's obvious that the answer
is wrong,because 11 show 0 times in the second line.
it's not about the sequence,it's just the number

Campbell Ritchie wrote:this sounds like one of the very few things I thought were diversions when I was on the diversions forum. I shall move it there.

you are the boss,man.

here is the problem,it might be some interview stuff from one company,never mind...

Give you 10 number [0，1，2，3，4，5，6，7，8，9],and we need you return me another 10 number to satisfy:
the number in the second line is the number of times in which the first line number show up in the second line..
it's hard to understand,I'll give an example:
for:[0,1,2,3,4,5,6,7,8,9]
we have: [6,2,1,0,0,0,1,0,0,0]
it means:the number '0' show 6 times in the second line,and the number '1' show 2 times in the second line......


I just solve it with Java.
you guys can try it. I will put my code on later if you need it..

Hey,Bud!I just found 2 mistakes in your program.Hope my tips could be helpful.
First,the IF statement should be in lower case.
Then,when you tried to throw an exception in a method,you should use "throw new xxxException();"
if (food == "Brocolli") { System.out.println("hello"); throw new BadFoodException(); }