Angela Li

thanks for making my code more concise, i was getting confused myself with all the if statements. It works now that I took your suggestion, thanks so much. I spent so long on this.

So, I expected the method to open up just the cell (x,y) if it is next to a mine so its not zero. But if it is zero or no mines are adjacent to it then I expect it to recursively open the cells around it. But the method is failing to recursively open.

This is my code for inspecting a cell in minesweeper, and it is not working as I had expected but I can't quite figure out what is wrong. Some help would be appreciated.
public boolean inspect(int x, int y) { if (board[x][y].getMined()) { board[x][y].setOpened(true); System.out.println("YOU LOSE"); return false; } else if (board[x][y].getSymbol() != '0') { board[x][y].setOpened(true); return true; } else for (int xval = x - 1; xval <= x + 1; xval++) { for (int yval = y - 1; yval <= y + 1; yval++) { if (xval > 0 && yval > 0 && xval <= row && yval <= col) { if (board[xval][yval].getOpened() || board[xval][yval].getFlagged() || board[xval][yval].getMined()) { } else if (board[xval][yval].getSymbol() != '0') { board[xval][yval].setOpened(true); } else if (board[xval][yval].getSymbol() == '0') { board[xval][yval].setOpened(true); inspect(xval, yval); } } } } return true; }

I'm writing minesweeper for class and we don't have to have a working GUI but we still need to have some type of grid that will show up on command prompt when the game is run. I am thinking about building a grid that will look something like this +-----+-----+
| X | X | for two cells. How should i design it so that i can connect the grid to my 2D arrays that represent what is inside the cell.
+-----+-----+

I can't get b to print out to be 32 and I keep getting 16.
public class Help { public static void doubler(int a) { a *= 2; } public static void main(String[] args) { int b=16; doubler(b); System.out.println("b is " +b); //b should be 32 } }


I also tried this but it also didn't work.
public class Help { static int b =16; public static void doubler(int a) { a *= 2; } public static void main(String[] args) { Help obj1 = new Help(); doubler(obj1.b); System.out.println("b is " + obj1.b); //b should be 32 } }

Thanks Rob, I didn't realize that.

I am trying to write a method that returns the list of factors when I input an integer.

private ArrayList<Integer> getIntegerFactors(int n) { ArrayList<Integer> factor = new ArrayList<Integer>(); if(n>0){ for (int i = 1; i <= n; i++) { if (n % i == 0) { factor.add(n / i); int m = -i; factor.add(n/m); } } return factor; } else if(n<0){ for (int i = 1; i >= n; i--) { if (n % i == 0) { factor.add(n / i); int m = -i; factor.add(n/m); } } } return factor; } }


When I run it using my main I get an error message:
Exception in thread "main" java.lang.ArithmeticException: / by zero
at QuadraticEqn.getIntegerFactors(QuadraticEqn.java:51)
at QuadraticEqn.main(QuadraticEqn.java:9)

What am I doing wrong?

Can you give me a suggestion on what to use besides a while loop?

I am writing a part of the craps game, and I am having trouble getting from the else loop to the while loop. My method just seems to ignore the while loop but I need the while loop to work.
public int processRoll(int total){ boolean firstRoll=true; int result; if(total==7 || total==11){ result=1; } else if(total==2 || total==3 || total==12){ result=-1; } else{ point=total; firstRoll=false; return 0; } while(firstRoll== false && (total!=7|| total!=point)){ return 0; }if(firstRoll==false && total==point){ result=1; point=0; firstRoll=true; }else if(firstRoll== false && total==7){ result=-1; point=0; firstRoll=true; } return result; }

Thanks Aniket, that was a stupid of me.

Thanks for the code suggestion, I appreciate it.

I'm suppose to write a class that asks for an int between one and five inclusive, then check if the int is really in the range, then use-- switch, case, break--to generate an appropriate message that corresponds with the number entered. And last return to the ask for int step.
This is what I have did so far but I am having trouble when I input an int inside the accepted range, it gives me the default.

import java.util.Scanner; public class OnetoFive{ public static void main(String[] args) { int i; boolean endNow = false; while(!endNow){ i=getChoice(); switch(i) { case 1: System.out.println("One is the loneliest number"); endNow=true; break; case 2: System.out.println("Two can be as bad as one"); endNow=true; break; case 3: System.out.println("Three Dog Night performed \"one\""); endNow=true; break; case 4: System.out.println("Four wasn't in the song :("); endNow=true; break; case 5: System.out.println("What did the five fingers say to...!"); endNow=true; break; default: System.out.println("Invalid number please enter a number within the range of 1-5 inclusive"); endNow=true; break; } } } public static char getChoice() { String prompt = "Type a number from one to five inclusive and press [ENTER]: "; System.out.print(prompt); Scanner keybd = new Scanner(System.in); return keybd.next().toCharArray()[0] ; //I know it has to do with this line but I'm not sure how to change from Char to Int } }